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VulnerabilityPublished Updated

CVE-2024-41035: Linux kernel · USB: core: Fix duplicate endpoint bug by clearing reserved bits in the descriptor

Source GCVE Database

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Not known to be exploited · CVSS 5.5 Medium.

Data as of 29 Oct 2026, 22:52 UTC

CVSS 3.1 base score
5.5Medium
How severe the flaw is on the 0–10 CVSS scale.
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:N/I:N/A:H

Exploitation evidence

  1. Disclosed: evidence found.

    CVE published 29 Jul 2024

  2. Detectable: no evidence on record.

    No public nuclei template indexed

  3. Weaponized: no evidence on record.

    No public exploit code indexed in Metasploit or Exploit-DB

  4. Exploited in the wild: no evidence on record.

    Not in CISA KEV and no source reports exploitation

  5. Observed by OffSeq Mirage: no evidence on record.

    No attack traffic recorded by OffSeq Mirage sensors

A missing step is not evidence of safety. Sources: cve.org (opens in a new tab), the Metasploit, Exploit-DB and nuclei-templates index as of 29 Oct 2026.

Description

In the Linux kernel, the following vulnerability has been resolved: USB: core: Fix duplicate endpoint bug by clearing reserved bits in the descriptor Syzbot has identified a bug in usbcore (see the Closes: tag below) caused by our assumption that the reserved bits in an endpoint descriptor's bEndpointAddress field will always be 0. As a result of the bug, the endpoint_is_duplicate() routine in config.c (and possibly other routines as well) may believe that two descriptors are for distinct endpoints, even though they have the same direction and endpoint number. This can lead to confusion, including the bug identified by syzbot (two descriptors with matching endpoint numbers and directions, where one was interrupt and the other was bulk). To fix the bug, we will clear the reserved bits in bEndpointAddress when we parse the descriptor. (Note that both the USB-2.0 and USB-3.1 specs say these bits are "Reserved, reset to zero".) This requires us to make a copy of the descriptor earlier in usb_parse_endpoint() and use the copy instead of the original when checking for duplicates.

References

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